代码

45 条评论

  • @ 2024-3-20 12:16:54

    硬币面值组合

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    	int n,s=0;
    	scanf("%d",&n);
    	for(int k=0;k<=n/5;k++){
    		for(int j=0;j<=n/2;j++){
    			for(int i=n;i>=0;i--){
    				if(i+j*2+k*5==n){
    					printf("%03d%12d%12d%12d\n",++s,i,j,k);
    				}
    			}
    		}
    	}
    	return 0;
    }
    
    • @ 2024-3-20 12:10:49

      生理周期

      #include<iostream>
      using namespace std;
      int main() {
      	int p, e, i, d;
      	cin >> p >> e >> i >> d;
      	for (int j = d + 1; j <= 21252 + d; j++) {
      		if ((j % 23 == p % 23) && (j % 28 == e % 28) && (j % 33 == i % 33)) {
      			cout << j - d;
      			return 0;
      		}
      	}
      	return 0;
      }
      
      • @ 2024-3-16 16:45:16

        井和绳子

        #include <iostream>
        using namespace std;
        int main() {
        	int k, n1, n2, n3, n4, n5;
        	cin >> k >> n1 >> n2 >> n3 >> n4 >> n5;
        	int B, C, D, E; 
        	for (int i = 1; i <= k * 100; i++) { 
        		for (int A = 0; A <= i; A++) { 
        			B = i - A * n1;
        			C = i - B * n2;
        			D = i - C * n3;
        			E = i - D * n4; 
        			if (!(A == B || A == C || A == D ||
        			    A == E || B == C || B == D || C == D || C == E || D == E || B == E)) {
        				if (E * n5 + A == i) { 
        					cout << i << " " << A << " " << B << " " << C << " " << D << " " << E << endl;
        					return 0;
        				}
        			}
        
        		}
        	}
        	cout << "not found";
        	return 0;
        }
        
        • @ 2024-3-10 19:27:15

          分形盒

          #include<bits/stdc++.h>
          using namespace std;
          #define MAX 730
          char maps[MAX][MAX];
          void printBox(int n,int x,int y){
          	if(n==1){
          		maps[x][y]='X';
          	}
          	else{
          		int m=pow(3,n-2);
          		printBox(n-1,x,y);
          		printBox(n-1,x+2*m,y);
          		printBox(n-1,x,y+2*m);
          		printBox(n-1,x+m,y+m);
          		printBox(n-1,x+2*m,y+2*m);
          	}
          }
          int main(){
          	int n;
          	cin>>n;
          	while(n!=-1){
          		int size=pow(3,n-1);
          		for(int i=0;i<size;i++){
          			for(int j=0;j<size;j++){
          				maps[i][j]=' ';
          				maps[i][size]='\0';
          			}
          		}
          		printBox(n,0,0);
          		for(int i=0;i<size;i++){
          		    printf("%s\n",maps[i]);
          		}
          		cout<<"-"<<endl;
          		cin>>n;
          	}
          	return 0;
          }
          
          • @ 2024-3-10 18:08:08

            拨钟问题

            #include<bits/stdc++.h>
            using namespace std;
            string mv[10] = {"", "ABDE", "ABC", "BCEF", "ADG", "BDEFH", "CFI", "DEGH", "GHI", "EFHI"};
            int o[9], t[9];
            int m[10], a[10];
            void move() {
            for (int i = 1; i <= 9; ++i) {
            string s = mv[i];
            for (int j = 1; j <= m[i]; ++j)
            for (int k = 0; k < s.length(); ++k)
            t[s[k] - 'A'] = (t[s[k] - 'A'] + 1) % 4;
            }
            }
            bool isAllZero() {
            for (int i = 0; i < 9; ++i)
            if (t[i] != 0)
            return false;
            return true;
            }
            int ss() {
            int sum = 0;
            for (int i = 1; i <= 9; ++i) {
            sum += m[i];
            }
            return sum;
            }
            int main() {
            int mn = 50;
            for (int i = 0; i < 9; ++i)
            cin >> o[i];
            for (m[1] = 0; m[1] < 4; ++m[1])
            for (m[2] = 0; m[2] < 4; ++m[2])
            for (m[3] = 0; m[3] < 4; ++m[3])
            for (m[4] = 0; m[4] < 4; ++m[4])
            for (m[5] = 0; m[5] < 4; ++m[5])
            for (m[6] = 0; m[6] < 4; ++m[6])
            for (m[7] = 0; m[7] < 4; ++m[7])
            for (m[8] = 0; m[8] < 4; ++m[8])
            for (m[9] = 0; m[9] < 4; ++m[9]) {
            memcpy(t, o, sizeof(o));
            move();
            if (isAllZero()) {
            int mt = ss();
            if (mt < mn) {
            mn = mt;
            memcpy(a, m, sizeof(m));
            }
            }
            }
            for (int i = 1; i <= 9; ++i) {
            while (a[i] > 0) {
            cout << i << ' ';
            a[i]--;
            }
            }
            return 0;
            }
            
            
            • @ 2024-2-18 19:52:22

              子串计算

              #include<bits/stdc++.h>
              using namespace std;
              int main(){
              	map<string,int> m;
              	string s="";
              	cin>>s;
              	int len=s.size();
              	for(int i=0;i<len;i++){
              		for(int j=1;j<=len-i;j++){
              			m[s.substr(i,j)]++;
              		}
              	}
              	for(map<string,int>::iterator it=m.begin();it!=m.end();it++){
              		if(it->second>1){
              			cout<<(*it).first<<" "<<it->second<<endl;
              		}
              	}
              	return 0;
              }
              
              • @ 2024-2-18 18:47:26

                P252 编辑距离P200 合唱队形 广义格雷码 课程冲突 拦截导弹 子串计算

                • @ 2024-1-27 17:26:52

                  余数相同

                  using namespace std;
                  int main() {
                  	int a,b,c;
                  	cin>>a>>b>>c;
                  	int x=2;
                  	for(int i=1;i<=1000000;i++){
                  		if(a%x==b%x&&b%x==c%x){
                  			cout<<x;
                  			return 0;
                  		}
                  		else{
                  		    x++;
                  		}
                  	}
                  	return 0;
                  }
                  
                  • @ 2024-1-27 12:15:52

                    因子问题

                    using namespace std;
                    int main(){
                    int m,n,a;
                    cin>>n>>m;
                    for(int i=1;i<=n;i++){
                    if(n%i==0&&n%(m-i)==0){
                    a=i;
                    cout<<a;
                    return 0;
                    }
                    }
                    cout<<"-1";
                    return 0;
                    }
                    
                    
                    • @ 2024-1-27 11:18:21
                      斐波那契数列
                      using namespace std;
                      long long a[1000000];
                      int main() {
                      	long long n;
                      	int m;
                      	cin>>m;
                      	int b[1000];
                      	for(int i=1;i<=m;i++){
                      		cin>>b[i];
                      	}
                      	a[1] = 1;
                      	a[2] = 1;
                      	for(int i=1;i<=m;i++) {
                      		for (long j = 3; j <= b[i]; j++) {
                      			a[j] = a[j - 1] + a[j - 2];
                      		}
                      		cout << a[b[i]] % 10000 << endl;
                      	}
                      	return 0;
                      }
                      
                      
                      • @ 2024-1-14 17:00:31

                        表达式求值

                        using namespace std;
                        char cc(char x,char y,char oper){
                        	bool a=(x=='V'),b=(y=='V'),ans;
                        	if(oper=='|')ans=(a||b);
                        	else if(oper=='&')ans=(a&&b);
                        	return ans?'V':'F';
                        }
                        char rr(char x){
                        	if(x=='V')return 'F';
                        	return 'V';
                        }
                        int main() {
                        	string in;
                        	int len,i,j;
                        	while(getline(cin,in)){
                        		stack<char>Oper,num;
                        		queue<char>s;
                        		len=in.length();
                        		i=len;
                        		in=" "+in;
                        		while(i>0){
                        			if(in[i]==' '){
                        				i--;
                        				continue;
                        			}
                        			else if(isalpha(in[i]))s.push(in[i--]);
                        			else if(in[i]=='!')s.push(in[i--]);
                        			else{
                        				if(in[i]=='&'||in[i]=='|'||in[i]==')'){
                        					Oper.push(in[i--]);//
                        				}
                        				else if(in[i]=='('){
                        					while(Oper.top()!=')'){
                        						s.push(Oper.top());
                        						Oper.pop();
                        					}
                        					Oper.pop();
                        					i--;
                        				}
                        			}
                        		}
                        		while(!Oper.empty()){
                        			s.push(Oper.top()),Oper.pop();
                        		}
                        		while(!s.empty()){
                        		    char ch=s.front();s.pop();
                        		    if(isalpha(ch))num.push(ch);
                        		    else{
                        				Oper.push(ch);
                        			}
                        			if(!num.empty()&&!Oper.empty()&&Oper.top()=='!'){
                        				char x=num.top();
                        				num.pop();
                        				Oper.pop();
                        				num.push(rr(x));
                        			}
                        			else if(num.size()>=2&&!Oper.empty()){
                        				char oper=Oper.top(),x,y;
                        				Oper.pop();
                        				x=num.top();num.pop();
                        				y=num.top();num.pop();
                        				num.push(cc(x,y,oper));
                        			}
                        		}
                        		cout<<num.top()<<endl;
                        	}
                        	return 0;
                        }
                        
                        • @ 2024-1-13 16:53:58

                          数列

                          using namespace std;
                          int main() {
                          	long long a[60];
                          	long long n;
                          	int m;
                          	cin>>m;
                          	int b[1000];
                          	for(int i=1;i<=m;i++){
                          		cin>>b[i];
                          	}
                          	a[1] = 1;
                          	a[2] = 1;
                          	for(int i=1;i<=m;i++) {
                          		for (long j = 3; j <= b[i]; j++) {
                          			a[j] = a[j - 1] + a[j - 2];
                          		}
                          		cout << a[b[i]] % 1000 << endl;
                          	}
                          	return 0;
                          }
                          
                          • @ 2024-1-13 16:29:14

                            数对

                            using namespace std;
                            int main() {
                            	int t, cnt, ans, a[30];
                            
                            	cnt = 0;
                            	ans = 0;
                            	int x;
                            	while (cin >> x) {
                            		if (x == 0) {
                            			break;
                            		}
                            		cnt++;
                            		a[cnt] = x;
                            	}
                            	for (int i = 1; i <= cnt - 1; i++) {
                            		for (int j = i + 1; j <= cnt; j++) {
                            			if (a[i] == 2 * a[j] || a[j] == 2 * a[i])
                            				ans++;
                            		}
                            	}
                            	cout << ans;
                            
                            	return 0;
                            }
                            
                            • @ 2024-1-13 16:14:53
                              分解因数
                              using namespace std;
                              int a;
                              void js(int b,int aa){
                              	if(aa==1){
                              		a++;
                              		return;
                              	}
                              	else{
                              		for(int i=b;i<=aa;i++){
                              			if(aa%i==0){
                              				js(i,aa/i);
                              			}
                              		}
                              	}
                              }
                              int main() {
                                  int n;
                                  cin>>n;
                                  while(n--){
                              		a=0;
                              		int aa;
                              		cin>>aa;
                              		js(2,aa);
                              		cout<<a<<endl;
                              	}
                              	
                              return 0;
                              }
                              
                              • @ 2024-1-13 15:56:40
                                不定方程求解
                                using namespace std;
                                int main() {
                                int a,b,c,num=0;
                                cin>>a>>b>>c;
                                int aa=c/a;
                                int bb=c/b;
                                for(int i=0;i<=aa;i++){
                                for(int j=0;j<=bb;j++){
                                if(a*i+b*j==c){
                                num++;
                                }
                                }
                                }
                                cout<<num;
                                return 0;
                                }
                                
                                • @ 2024-1-13 15:54:27
                                  完美立方
                                  using namespace std;
                                  int main(){
                                  	int N;
                                  	int a,b,c,d;
                                  	scanf("%d",&N);
                                  	for(a=2;a<=N;a++){
                                  		for(b=2;b<=N-1;b++){
                                  			for(c=b;c<=N-1;c++){
                                  				for(d=c;d<=N-1;d++){
                                  					if((b<=c&&c<=d&&d<=a)&&(a*a*a==b*b*b+c*c*c+d*d*d)){
                                  						cout<<"Cube = "<<a<<", Triple = ("<<b<<","<<c<<","<<d<<")"<<endl;
                                  					}
                                  				}
                                  			}
                                  		}
                                  	}
                                  	return 0;
                                  }
                                  
                                  • @ 2024-1-7 18:57:36

                                    找和为k的两个元素

                                    #include <iostream>
                                    using namespace std;
                                    int main() {
                                    	int n,k,a[1000],sign=0;
                                    	cin>>n>>k;
                                    	for(int i=1;i<=n;i++){
                                    		cin>>a[i];
                                    	}
                                    	for(int i=1;i<=n-1;i++){
                                    		for(int j=i+1;j<n;j++){
                                    			if(k==a[i]+a[j]){
                                    				sign=1;
                                    				break;
                                    			}
                                    		}
                                    		if(1==sign){
                                    			break;
                                    		}
                                    	}
                                    	if(sign>0){
                                    		cout<<"yes";
                                    	}
                                    	else{
                                    		cout<<"no";
                                    	}
                                    	return 0;
                                    }
                                    
                                    • @ 2024-1-7 18:46:03

                                      流感传染

                                      #include<bits/stdc++.h>
                                      using namespace std;
                                      char a[101][101], aa[101][101];
                                      int n, m, cnt = 0;
                                      int net[4][4] = {{0, 1}, {1, 0}, {-1, 0}, {0, -1}};
                                      void gr(int x, int y) {
                                      int dx, dy;
                                      for (int i = 0; i < 4; i++) {
                                      dx = x + net[i][0];
                                      dy = y + net[i][1];
                                      if (dx > 0 && dx <= n && dy > 0 && dy <= n && a[dx][dy] == '.') {
                                      aa[dx][dy] = '@';
                                      }
                                      }
                                      }
                                      int main() {
                                      cin >> n;
                                      for (int i = 1; i <= n; i++){
                                      for (int j = 1; j <= n; j++) {
                                      cin >> a[i][j];
                                      aa[i][j] = a[i][j];
                                      }
                                      }	
                                      cin >> m;
                                      for (int k = 2; k <= m; k++) {
                                      for (int i = 1; i <= n; i++){
                                      for (int j = 1; j <= n; j++) {
                                      if (a[i][j] == '@')gr(i, j);
                                      }
                                      }	
                                      for (int i = 1; i <= n; i++){
                                      for (int j = 1; j <= n; j++)
                                      a[i][j] = aa[i][j];
                                      }
                                      }
                                      for (int i = 1; i <= n; i++){
                                      for (int j = 1; j <= n; j++)
                                      if (a[i][j] == '@')cnt++;
                                      }
                                      cout << cnt << endl;
                                      return 0;
                                      }
                                      
                                      • @ 2024-1-7 18:44:04

                                        苹果消消乐

                                        #include<bits/stdc++.h>
                                        using namespace std;
                                        int t,n,m;
                                        int a[200];
                                        int main(){
                                        	cin>>t;
                                        	a[0]=0;
                                        	int maxx=0;
                                        	while(t--){
                                        		cin>>n>>m;
                                        		a[n+1]=101;
                                        		maxx=0;
                                        		for(int i=1;i<=n;i++){
                                        			cin>>a[i];
                                        		}
                                        		if(n<=m){
                                        			cout<<100<<endl;
                                        		}
                                        		else{
                                        			for(int i=1;i<=n-m+1;++i){
                                        				maxx=max(maxx,a[i+m]-a[i-1]-1);
                                        			}
                                        			cout<<maxx<<endl;
                                        		}
                                        	}
                                        	return 0;
                                        }
                                        
                                        • @ 2024-1-7 18:42:21

                                          踩方格

                                          #include<bits/stdc++.h>
                                          using namespace std;
                                          int walk(int n,int as){
                                          if(n>0){
                                          switch (as) {
                                          case 1:
                                          return walk(n-1,1)+walk(n-1,2);
                                          break;
                                          case 2:
                                          return walk(n-1,1)+walk(n-1,2)+walk(n-1,3);
                                          break;
                                          case 3:
                                          return walk(n-1,2)+walk(n-1,3);
                                          break;
                                          }
                                          }
                                          else{
                                          return 1;
                                          }
                                          }
                                          int main(){
                                          int n;
                                          cin>>n;
                                          int sum=walk(n-1,1)+walk(n-1,2)+walk(n-1,3);
                                          cout<<sum;
                                          return 0;
                                          }
                                          
                                          • @ 2024-1-7 18:39:13

                                            Minecraft

                                            using namespace std;
                                            int main(){
                                            std::ios::sync_with_stdio(false);
                                            int n,minn=1<<30;
                                            cin>>n;
                                            for(int i=1;i<=n;i++){
                                            for(int j=1;j<=n;j++){
                                            int k=n/i/j;
                                            if((double)k==(double)n/i/j)
                                            if(2*(i*j+i*k+k*j)<minn)
                                            minn=2*(i*j+i*k+k*j);
                                            }	
                                            }
                                            cout<<minn;
                                            return 0;
                                            }
                                            
                                            
                                            • @ 2024-1-7 18:36:30

                                              上台阶

                                              #include<bits/stdc++.s>
                                              using namespace std;
                                              string a[200];
                                              string jia(string s1, string s2) {
                                              	int a[100], b[100], c[100];
                                              	memset(a, 0, sizeof(a));
                                              	memset(b, 0, sizeof(b));
                                              	memset(c, 0, sizeof(c));
                                              	if (s1.size() < s2.size()) {
                                              		swap(s1, s2);
                                              	}
                                              	a[0] = s1.size();
                                              	b[0] = s2.size();
                                              	c[0] = b[0];
                                              	for (int i = 1; i <= a[0]; ++i) {
                                              		a[i] = s1[a[0] - i] - '0';
                                              	}
                                              	for (int i = 1; i <= b[0]; ++i) {
                                              		b[i] = s2[b[0] - i] - '0';
                                              	}
                                              	for (int i = 1; i <= a[0]; ++i) {
                                              		c[i + 1] = (c[i] + a[i] + b[i]) / 10;
                                              		c[i] = (c[i] + a[i] + b[i]) % 10;
                                              	}
                                              	if (c[c[0] + 1]) {
                                              		c[0]++;
                                              	}
                                              	string s3;
                                              	for (int i = c[0]; i > 0; --i) {
                                              		s3 += c[i] + '0';
                                              	}
                                              	return s3;
                                              }
                                              int main() {
                                              	int n;
                                              	a[0] = "0";
                                              	a[1] = "1";
                                              	a[2] = "2";
                                              	a[3] = "4";
                                              	for (int i = 4; i <= 100; i++) {
                                              		a[i] = jia(a[i-1],jia(a[i-2],a[i-3]));
                                              	}
                                              	while (cin >> n) {
                                              		if (n == 0) {
                                              			return 0;
                                              		}
                                              		cout << a[n] << endl;
                                              	}
                                              	return 0;
                                              }
                                              
                                              • @ 2024-1-7 18:27:26

                                                猴子吃桃

                                                #include <bits/stdc++.h>
                                                using namespace std;
                                                int ans[100000000];
                                                int main(){
                                                int n;
                                                cin>>n;
                                                ans[1]=3;
                                                for(int i=2;i<=n;i++){
                                                ans[i]=ans[i-1]*n+1;
                                                }
                                                cout<<ans[n];
                                                return 0;
                                                }
                                                
                                                
                                                • @ 2024-1-7 18:25:39

                                                  鸡兔同笼

                                                  #include <iostream>
                                                  using namespace std;
                                                  int main(){
                                                  int a;
                                                  cin>>a;
                                                  if(a%2!=0){
                                                  cout<<"0 0";
                                                  return 0;
                                                  }
                                                  if(a%4==0){
                                                  cout<<a/4<<" "<<a/2;
                                                  }
                                                  else{
                                                  cout<<a/4+1<<" "<<a/2;
                                                  }
                                                  return 0;
                                                  }
                                                  
                                                  
                                                  • @ 2024-1-7 18:21:33

                                                    质数的和与积

                                                    #include<bits/stdc++.h>
                                                    using namespace std;
                                                    int p[(int)2e4];
                                                    
                                                    int main(){
                                                    	p[1] = 1; 
                                                    	p[2] = 0;
                                                    	int temp = sqrt((int)1e4);
                                                    	for(int i=2;i<=temp;i++){
                                                    		if(p[i]==0){
                                                    			for(int j=i*2;j<=(int)1e4;j+=i){
                                                    				p[j] = 1;
                                                    			}
                                                    		}
                                                    	}
                                                    	int s;
                                                    	cin>>s;
                                                    	int Max = 0;
                                                    	for(int i=1;i<=(int)1e4;i++){
                                                    		if(p[i] == 0){
                                                    			int t = s - i;
                                                    			if(t>=1&&p[t]==0){
                                                    				if(t*i>=Max){
                                                    					Max = t*i;
                                                    				}
                                                    			}
                                                    		}
                                                    	}
                                                    	cout<<Max;
                                                    	return 0;
                                                    }
                                                    
                                                    • @ 2024-1-7 18:19:32

                                                      和数

                                                      #include<bits/stdc++.s>
                                                      using namespace std;
                                                      int a[200];
                                                      int main(){
                                                      int n;
                                                      int s=0;
                                                      cin>>n;
                                                      for(int i=1;i<=n;i++){
                                                      cin>>a[i];
                                                      }
                                                      for(int i=1;i<=n;i++){
                                                      bool f=0;
                                                      for(int j=1;j<=n;j++){
                                                      for(int t=j+1;t<=n;t++){
                                                      if(a[i]==a[j]+a[t]){
                                                      f=1;
                                                      }
                                                      }
                                                      }
                                                      if(f==1){
                                                      s++;
                                                      }
                                                      }
                                                      cout<<s;
                                                      return 0;
                                                      }
                                                      
                                                      • @ 2024-1-7 18:13:03

                                                        和数

                                                        #include<bits/stdc++.h>
                                                        using namespace std;
                                                        int a[200];
                                                        int main(){
                                                        	int n;
                                                        	int s=0;
                                                        	cin>>n;
                                                        	for(int i=1;i<=n;i++){
                                                        		cin>>a[i];
                                                        	}
                                                        	for(int i=1;i<=n;i++){
                                                        		bool f=0;
                                                        		for(int j=1;j<=n;j++){
                                                        			for(int t=j+1;t<=n;t++){
                                                        				if(a[i]==a[j]+a[t]){
                                                        					f=1;
                                                        				}
                                                        			}
                                                        		}
                                                        		if(f==1){
                                                        			s++;
                                                        		}
                                                        	}
                                                        	cout<<s;
                                                        	return 0;
                                                        }
                                                        
                                                        • @ 2024-1-6 20:40:02

                                                          image

                                                          • @ 2024-1-6 20:38:46

                                                            image

                                                            • @ 2024-1-6 20:10:12

                                                              image

                                                              • @ 2024-1-6 20:08:27

                                                                田忌赛马

                                                                #include <bits/stdc++.h>
                                                                using namespace std;
                                                                int b[100];
                                                                int N,X;
                                                                int t=0;
                                                                bool check(int arr[]){
                                                                	int sum=0;
                                                                	for(int i=1;i<=N;i++){
                                                                		if(arr[i]-b[i]>=X){
                                                                			sum+=1;
                                                                		}
                                                                	}
                                                                	if(sum>=t){
                                                                		return true;
                                                                	}
                                                                	else{
                                                                		return false;
                                                                	}
                                                                }
                                                                int main(){
                                                                	cin>>N>>X;
                                                                	for(int i=1;i<=N;i++){
                                                                		cin>>b[i];
                                                                	}
                                                                	int a[100];
                                                                	for(int i=1;i<=N;i++){
                                                                		a[i]=i;
                                                                	}
                                                                	t=ceil(N/2.0);
                                                                	do{
                                                                		if(check(a)){
                                                                			for(int i=1;i<=3;i++){
                                                                				cout<<a[i]<<" ";
                                                                			}
                                                                			cout<<endl;
                                                                		}
                                                                	}while(next_permutation(a+1,a+N+1));
                                                                	return 0;
                                                                }
                                                                
                                                                • @ 2024-1-6 20:04:05
                                                                  #include<iostream>
                                                                  #include<iomanip>
                                                                  #include<algorithm>
                                                                  #include<cmath>
                                                                  using namespace std;
                                                                  int b[100];
                                                                  int N, X;
                                                                  int t;
                                                                  bool check(int arr[]) {
                                                                  	int sum = 0;
                                                                  	for (int i = 1; i <= N; i++) {
                                                                  		if (arr[i] - b[i] >= X) {
                                                                  			//TODO
                                                                  			sum += 1;
                                                                  		}
                                                                  	}
                                                                  	if (sum >= t) {
                                                                  		//TODO
                                                                  		return true;
                                                                  	} else {
                                                                  		return false;
                                                                  	}
                                                                  }
                                                                  int main() {
                                                                  	/*
                                                                  	next_permutation()
                                                                  	*/
                                                                  	cin >> N >> X;
                                                                  	for (int i = 1; i <= N; i++) {
                                                                  		//TODO
                                                                  		cin >> b[i];
                                                                  	}
                                                                  	int a[100];
                                                                  	for (int i = 1; i <= N; i++) {
                                                                  		a[i] = i;
                                                                  	}
                                                                  	t = ceil(N / 2.0);
                                                                  	do {
                                                                  		//输入判断条件,这里用cout输出
                                                                  		if (check(a)) {
                                                                  			for (int i = 1; i <= 3; i++) {
                                                                  				cout << a[i]<<" ";
                                                                  			}
                                                                  			cout << endl;
                                                                  		}
                                                                  	} while (next_permutation(a + 1, a + N + 1));
                                                                  	return 0;
                                                                  }
                                                                  
                                                                  • @ 2024-1-6 19:31:26

                                                                    image

                                                                    • @ 2024-1-6 19:28:23

                                                                      上台阶

                                                                      #include <bits/stdc++.h>
                                                                      using namespace std;
                                                                      long long a[200];
                                                                      int main(){
                                                                      	int n;
                                                                      	//cin>>n;
                                                                      	a[0]=0;
                                                                      	a[1]=1;
                                                                      	a[2]=2;
                                                                      	a[3]=4;
                                                                          for(int i=4;i<=100;i++){
                                                                      		a[i]=a[i-1]+a[i-2]+a[i-3];
                                                                      	}
                                                                      	//cout<<a[n];
                                                                      	while(cin>>n){
                                                                      		if(n==0){
                                                                      			return 0;
                                                                      		}
                                                                      		cout<<a[n]<<endl;
                                                                      	}
                                                                      	return 0;
                                                                      }
                                                                      
                                                                      • @ 2024-1-6 19:26:10

                                                                        上台阶

                                                                        #include <bits/stdc++.h>
                                                                        using namespace std;
                                                                        long long a[200];
                                                                        int main(){
                                                                        	int n;
                                                                        	//cin>>n;
                                                                        	a[0]=0;
                                                                        	a[1]=1;
                                                                        	a[2]=2;
                                                                        	a[3]=4;
                                                                            for(int i=4;i<=n;i++){
                                                                        		a[i]=a[i-1]+a[i-2]+a[i-3];
                                                                        	}
                                                                        	//cout<<a[n];
                                                                        	while(cin>>n){
                                                                        		if(n==0){
                                                                        			return 0;
                                                                        		}
                                                                        		cout<<a[n]<<endl;
                                                                        	}
                                                                        	return 0;
                                                                        }
                                                                        
                                                                        • @ 2024-1-6 17:04:27

                                                                          爬楼

                                                                          #include<bits/stdc++.h>
                                                                          using namespace std;
                                                                          long long a[200];
                                                                          int main(){
                                                                          	int n;
                                                                          	a[1]=0;
                                                                          	a[2]=1;
                                                                          	a[3]=1;
                                                                          	for(int i=4;i<=50;i++){
                                                                          		a[i]=a[i-2]+a[i-3];
                                                                          	}
                                                                          	do{
                                                                          		cin>>n;
                                                                          		if(n){
                                                                          			cout<<a[n]<<endl;
                                                                          		}
                                                                          	}while(n);
                                                                          	return 0;
                                                                          }
                                                                          
                                                                          • @ 2023-12-31 19:28:16

                                                                            生成括号

                                                                            using namespace std;
                                                                            int n;
                                                                            char a[2]={'(',')'};
                                                                            char ans[22];
                                                                            bool pd(char b[]){
                                                                            	int numl=0,numr=0;
                                                                            	for(int i=0;i<2*n;++i){
                                                                            		if(b[i]=='('){
                                                                            			numl++;
                                                                            		}
                                                                            		else{
                                                                            			numr++;
                                                                            		}
                                                                            		if(numl<numr){
                                                                            			return false;
                                                                            		}
                                                                            	}
                                                                            	if(numl==numr){
                                                                            		return true;
                                                                            	}
                                                                            	else{
                                                                            		return false;
                                                                            	}
                                                                            }
                                                                            void dfs(int dep){
                                                                            	if(dep==2*n){
                                                                            		if(pd(ans)){
                                                                            			for(int i=0;i<2*n;++i){
                                                                            				cout<<ans[i];
                                                                            			}
                                                                            			cout<<endl;
                                                                            		}
                                                                            		return;
                                                                            	}
                                                                            	for(int i=0;i<=1;++i){
                                                                            		ans[dep]=a[i];
                                                                            		dfs(dep+1);
                                                                            	}
                                                                            }
                                                                            int main() {
                                                                            	cin>>n;
                                                                            	dfs(0);
                                                                            	return 0;
                                                                            }
                                                                            
                                                                            • @ 2023-12-31 18:36:41

                                                                              铺砖

                                                                              using namespace std;
                                                                              string s[251];
                                                                              string jia(string s1,string s2){
                                                                              	int a[100],b[100],c[100];
                                                                              	memset(a,0,sizeof(a));
                                                                              	memset(b,0,sizeof(b));
                                                                              	memset(c,0,sizeof(c));
                                                                              	if(s1.size()<s2.size()){
                                                                              		swap(s1,s2);
                                                                              	}
                                                                              	a[0]=s1.size();
                                                                              	b[0]=s2.size();
                                                                              	c[0]=b[0];
                                                                              	for(int i=1;i<=a[0];++i){
                                                                              		a[i]=s1[a[0]-i]-'0';
                                                                              	}
                                                                              	for(int i=1;i<=b[0];++i){
                                                                              	    b[i]=s2[b[0]-i]-'0';
                                                                              	}
                                                                              	for(int i=1;i<=a[0];++i){
                                                                              		c[i+1]=(c[i]+a[i]+b[i])/10;
                                                                              		c[i]=(c[i]+a[i]+b[i])%10;
                                                                              	}
                                                                              	if(c[c[0]+1]){
                                                                              		c[0]++;
                                                                              	}
                                                                              	string s3;
                                                                              	for(int i=c[0];i>0;--i){
                                                                              		s3+=c[i]+'0';
                                                                              	}
                                                                              	return s3;
                                                                              }
                                                                              int main(){
                                                                              	s[0]="0";
                                                                              	s[1]="1";
                                                                              	s[2]='3';
                                                                              	for(int i=3;i<=250;i++){
                                                                              		s[i]=jia(s[i-1],jia(s[i-2],s[i-2]));
                                                                              	}
                                                                              	int n;
                                                                              	while(cin>>n){
                                                                              		cout<<s[n]<<endl;
                                                                              	}
                                                                              	return 0;
                                                                              }
                                                                              
                                                                              • @ 2023-12-30 20:00:54

                                                                                image

                                                                                铺砖

                                                                                • @ 2023-12-30 20:00:00

                                                                                  铺砖

                                                                                  image image

                                                                                  • @ 2023-12-30 19:56:27

                                                                                    生成括号 image

                                                                                    image

                                                                                    image

                                                                                    • @ 2023-12-30 19:55:34

                                                                                      202103C语言三级真题

                                                                                      • @ 2023-12-30 19:55:07

                                                                                        202303C语言三级真题

                                                                                        202212C语言三级真题

                                                                                        • @ 2023-12-30 19:13:41
                                                                                          http://noi.openjudge.cn/
                                                                                          
                                                                                          • @ 2023-12-30 19:12:32

                                                                                            试卷名称 标题

                                                                                            http://noi.openjudge.cn/
                                                                                            
                                                                                            #include <iostream>
                                                                                            #include <iomanip>
                                                                                            using namespace std;
                                                                                            
                                                                                            int main(){
                                                                                            	int a;
                                                                                            	cin>>a;
                                                                                            	cout<<"---"<<setw(3)<<left<<fixed<<setprecision(3)<<a<<"---";//1234
                                                                                                return 0;
                                                                                            }
                                                                                            

                                                                                            image

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